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# Dictionary - Word Frequency

### Step One

Consider the following dictionary:

words={"the":3,"kenyon":2,"college":4,"learn":6,"python":2}

Can we write code to add 1 to the number associated with Kenyon?

### Step Two

Write a function countWord(d, w) to add a word to the dictionary d, with a count of 1, if it not in the dictionary, and increment the count if it is in the dictionary.

Note that we can tell if a word key is in the dict with:

if word in freqList.keys(0):

### Step Three

Write a function countWords(d,s) that we pass a dictionary d and a string s to it. For each word in the string it adds the word to the dictionary if it's not there, with a 1 as the count, or it increments that count for that word is if is.

### Step Four

Consider the code we wrote to find and count the words in Emily Dickenson. Can we improve this codes with a dictionary?

Now let's review a solution that counts a single word:

Let's fork this and try to modify it.

##### Step Five

Modify the code to use the countWords function to first create an index of all the words in Emily Dickinson.

##### Step Six

Write a function lookupFreq(w) that looks up the frequency of word w, and return the number. If the word is not in the list, return 0. Create a loop to call this function after asking for a word.

##### Step Seven

Write a function displayWordFreq(d) that, giving dictionary d from above, displays all the words and their associated frequency. amplitude 1
awe 2
prospective 1
gold 3
lay 2
unmentioned 1
develops 1
weed 1

##### Step 8

Consider how you can print out a sorted list of words with frequency? You can't sort a dictionary.

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Topic revision: r3 - 2020-03-18 - JimSkon

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